Conditions for Samples to undergo Precision Assessment

For a sample scheme analyte to undergo precision assessment and have its Precision Status set to Not Tested, the sample scheme analyte must not have a result, in which case its Workflow Status would be Not Started or Repeat.

For a sample scheme analyte to undergo precision assessment and have its Precision Status set to Not Required, the sample scheme analyte's Workflow Status must be Analysed or Check and at least one of the following conditions must be met:

  • The sample scheme analyte's Data Type is something other than Numeric or Numeric Only (which means that the Numeric Final Value does not exist for the first sample of the pair)
  • Both the sample's Primary Analytical Type and Secondary Analytical Type are something other than Duplicate or Replicate
  • The sample scheme analyte's QC Active check box is cleared
  • The sample's Duplicate Original Sample Code does not link to an in-scope sample
  • The original parent sample scheme analyte's Data Type is something other than Numeric or Numeric Only (which means that the Numeric Final Value does not exist for the second sample of the pair)

For a sample scheme analyte to undergo precision assessment and have its Precision Status set to either Pass, or one of the warning or failure statuses, the sample scheme analyte's Workflow Status must be Analysed or Check (that is, even if the result exceeds a critical detection limit, precision assessment still takes place) and all of the following conditions must be met:

  • The sample scheme analyte's Data Type is Numeric and the result is actually numeric, or Numeric Only (which means that the Numeric Final Value exists for the first sample of the pair)
  • The sample's Primary Analytical Type or Secondary Analytical Type must be Duplicate or Replicate
  • The sample scheme analyte's QC Active must be selected
  • The sample's Duplicate Original Sample Code must link to an in-scope sample
  • The original parent sample scheme analyte's Data Type is Numeric and the result is actually numeric, or Numeric Only (which means that the Numeric Final Value exists for the second sample of the pair)